What is bond order? How we can determine it? Please basics
Dec 3, 2016 · A conceptual approach is to simply count electrons in a bond and treat each bonding valence electron as half a bond order. This works for many cases, except for when the highest-energy electron is in an antibonding molecular orbital. SIMPLE CASE For example, the bond order of :"N"-="N": fairly straightforward because it's a triple bond, and each bonding …
Using the MO diagram of #"NO"#, calculate the bond order
Aug 29, 2017 · The MO diagram for "NO" is as follows (Miessler et al., Answer Key): (The original was this; I added the orbital depictions and symmetry labels. For further discussion on the orbital energy ordering being "N"_2-like, see here and comments.) Quick overview of what the labels correspond to what MOs: 1a_1 is the sigma_(2s) bonding MO. 2a_1 is the sigma_(2s)^"*" …
How do I calculate the bond order for H2- and H2+? - Socratic
Apr 1, 2017 · I'm assuming you mean "H"_2^(-) vs. "H"_2^(+). Well, build the molecular orbital (MO) diagram. Each hydrogen atom contributes one electron, and thus, "H"_2^(-) has three electrons while "H"_2^(+) has one. Each hydrogen atom contributes one 1s atomic orbital, and thus, the orbitals overlap according to MO theory to form one sigma_(1s) and one …
How do I determine the bond angle in a molecule? - Socratic
Dec 30, 2013 · There are three basic steps to determining the bond angles in a molecule: > 1. Write the Lewis dot structure for the molecule. Assume that you must determine the bond angles in "BF"_3. "B" is less electronegative than "F", so "B" becomes the central atom. If we have three "F" atoms, that means that we are going to use all three electrons from the "B". This gives us …
By writing molecular orbital configuration for NO,CO,O2 ... - Socratic
Mar 18, 2018 · Hence, the bond order of #"NO"# is either #2.5# or #3.5#, depending on whether the last electron went into a bonding or antibonding MO. The MO diagram of #"NO"# is: The last electron is in fact in the #2b_1# antibonding MO, so the bond order of #"NO"# has decreased by #1/2# relative to #"NO"^(+)# or #"CO"#. Therefore the bond order is #color ...
What is the bond order in NO2+? - Socratic
Dec 20, 2017 · Its bond order is 2. If you mean "NO"^(2+), the MO diagram of "NO" is: Thus, "NO"^(2+) loses the 2b_1 antibonding electron and the 3a_1 bonding electron, and its bond order is around 2.5. This does not match the given answers, but you had left that possibility open.
Determine the bond order of the "C"-"O" bond in the following …
Apr 30, 2017 · We should notice that for the pi bond order, there will be 2 pi electrons delocalized onto three bonds, making each bond on average having 2/3 of a pi electron, thereby giving a pi bond order of 1/3. Since perfect single bonds have a bond order of 1, the total bond order on "CO"_3^(2-) is bb(1.bar(33)).
What is the molecular orbital diagram for #C_2^-#? - Socratic
Dec 2, 2016 · Here's what I got. The problem provides you with the MO diagram for the "C"_2 molecule, so all you really have to do here is add an electron to that diagram. You need to add an electron and not remove one because of the overall negative charge that exists on the molecule. As you know, a neutral carbon atom has a total of 6 electrons. This, of course, implies that a …
How do you find the bond order of #NO_3^-#? - Socratic
Oct 10, 2016 · The bond order is the average, "4 electron pairs" / "3 bonds" = "4/3 electron pairs per bond". The Lewis structure of nitrate ion is unusual because it features 3 formal charges in that the nitrogen is quaternized and formally cationic, and 2 of the oxygen atoms have formal negative charges. Of course, the sum of the charges +1+2xx(-1)=-1 for a uninegative ion. See …
How can I calculate the bond order of benzene? - Socratic
Apr 11, 2014 · You draw the molecular orbitals. Then you add electrons and count the number of bonding and antibonding electrons. The bond order of a bond is half the difference between the number of bonding and antibonding electrons. BO = ½(B – A) The C-C σ Bonds Each C-C σ bond is a localized bond. It has 2 bonding electrons and 0 nonbonding electrons. σ BO = ½(B – A) = …